Scoring skewered movements
ONE point for every pair you tie with, TWO points for every pair you beat.
This is basis of all match point scoring – it doesn’t change.
Incomplete movements can produce short boards. The number of match points available from the board is going to be less than that from a complete board. The mps must be increased to normalise the board and make it equal in weight to a complete board. A short board should be scored as though it had been played the same number of times as a complete board and so be scored-out-of the same mps total as a complete board.
Short boards are initially scored as-is and then the awarded match points are adjusted or normalised using the formula:
MP x SF + (SF-1) = Normalised Score
(MP are the as-is scores, SF is the scaling factor)
To scale 2 results to 3 results use an SF of 3/2 |
||
AS-IS |
Normalised |
AsDecimal |
2 |
3 +1/2 |
3.50 |
1 |
1 +1/2 |
2.0 |
0 |
0 +1/2 |
0.50 |
To scale 3 results to 4 results use an SF of 4/3 or 1.33 |
||
AS-IS |
Normalised |
AsDecimal |
4 |
16/3+1/3 |
5.66 |
3 |
4+1/3 |
4.33 |
2 |
8/3+1/3 |
3.00 |
1 |
4/3+1/3 |
1.66 |
0 |
1/3 |
0.33 |
Normalising works as follows, consider a short board with three results:
NSScore NSMatchPoints
150 3
150 3
80 0
There are 2 results of plus 150 and 1 result of plus 80
If the board were to be played 30 times your best guess is
30/3 x2 = 20 results of 150 and 30/3 x1=10 results of 80
THE SAME LOGIC IS USED FOR 4X
If the board were to be played 4 times your best guess is
4/3 x 2 results of 150 and 4/3 x 1 results of 80
i.e. 2+2/3 of 150 and 1+1/3 of 80
Apply the rule::
One MP for each pair you tie with and Two MPs for each pair you beat so….
If your score is 150 you tie with 1+2/3 other pairs (don’t forget to subtract the 1 that is you) and you beat 1+1/3 pairs:
1.66x1+1.33x2 = 4.33, as specified above in the table for normalising or scaling a 3 MPs score
If you have a score of 80 you tie with 1/3 pairs (don’t forget to subtract the 1 that is you) and you beat 0 pairs:
0.33x1+0.0x2 = 0.33, as specified above in the table for normalising or scaling 0 MPs score
The formula at the top is obtained using the same logic with a little simple algebra:
E= number of pairs (on your side) with an equal contract score* (includes you)
L= number of pairs (on your side) with a contract score less than the E score.
λ = scale factor
* remember EW pluses are treated as NS minuses and vice versa
One MP for each pair you tie with and Two MPs for each pair you beat
as-is MP score = (E-1)×1 + (L)×2 = [(E-1) + 2L]
normalised score = (E×λ -1)×1 + (L×λ)×2 =(Eλ -1) + 2Lλ
= (Eλ – λ + λ -1) + 2Lλ
= (Eλ – λ) + (λ -1) + 2Lλ
= (E –1) ×λ + (λ -1) + 2Lλ
= (E –1)λ + 2Lλ + (λ -1)
= [(E -1) + 2L] ×λ + (λ -1)
= MP ×SF + (SF-1)
A three result board has a maximum of 4mp and total of 6mp for each NS and EW pair set
NSScore |
NS MPs |
EW MPs |
NS MPs |
EW MPs |
|
As is |
As is |
Normlsd UP |
Normlsd UP |
150 |
4 |
0 |
5.66 |
0.33 |
100 |
2 |
2 |
3 |
3 |
80 |
0 |
4 |
0.33 |
5.66 |
total |
6 |
6 |
9 |
9 |
A four result board has a maximum of 6mp and total of 12mp for each NS and EW pair set and a par of 3mps
NSScore |
NS MPs |
EW MPs |
160 |
6 |
0 |
110 |
3 |
3 |
110 |
3 |
2 |
-50 |
0 |
4 |
total |
12 |
12 |
The three result board after normalising has a total of 9mps but then by adding in PAR results of 3mps for NS & EW PHANTOM PAIRS the board the total is 12mps just like four board. Indeed the board IS now scored out of 12 but only 3 results appear. Also the Normalised UP scores for NS and EW add up (across) to 6 just like the four board.
Note: There is a slight ambiguity with the phrase ‘scored-out-of’. It can apply to whole board or just the board’s NS or EW pair sets totals each equal to half the value for the board or just the top value.
So simply score as-is, multiply by a scale factor say 4/3 and add the offset (4/3-1)= 1/3 and treat the board as scored-out-of 12.
Using a scale factor of 5/3 you can scale up or normalise a 3 result board to 5 results and so on. Or you can scale up 3 to 4 and then scale the 4 to 5 to get the same answer as scaling 3 5 direct.
You can never secure a real TOP on a normalised short board because there is always a chance that had the board been played one more time the best score becomes a second. Similarly you can’t get a real BOTTOM either. But for scoring purposes (calculating the overall percentages) the board is deemed to offer a real TOP equal to a complete board.
Times |
Value of |
Board scored |
PAR |
Played |
TOP |
out of |
Value |
3 |
4 |
12 |
2 |
4 |
6 |
24 |
3 |
5 |
8 |
40 |
4 |
6 |
10 |
60 |
5 |
X |
2(X-1) |
2X(X-1) |
X-1 |
The score table is a reconciliation of all board results (normalised if appropriate) in columns with the mp scores aligned by row to correspond to each pair , the row total being that pair’s score. These rows totals are converted to a percentage of the maximum possible score - (boards played) x (value of a TOP). The max is usually the same for all pairs, but if the movement has a sit-out and ends before completion, some deprived pairs will have played fewer boards. A proportional max possible score is determined for each pair (no boards played by the pair) x (TOP value).
The percentage is then simply 100 x Score Total / Max Score Possible
An alternative but less popular method is to replace gaps(the missing results) in the reconciliation table with PARs - (half real TOPS), but only where a set of boards would have been played had the movement been completed: This allows the same max possible score value to be used for all pair percentages. The GAP PAR method should assist slightly any deprived weaker pairs and diminish slightly any deprived stronger pairs.
The choice between the proportional scoring above and using gap pars is one of attitude about the leading pairs. A leading place achieved by a deprived strong pair despite the slight disadvantage of included PARs, must be considered a just and worthy reward as opposed to a placement arising from numerical conjuring. Occasionally a strongish pair, having a bad bridge day, may benefit from having a PAR score assigned rather than the proportional equivalent of a pair average score, but that pair wouldn’t then be on track for a leading place anyway.
Click HERE for a follow up page on accommodating a set score award(60:60) by director